Markov Equation With Fibonacci Components

Florian Luca, Anitha Srinivasan

˜The œFibonacci quarterly · 2018 · 16 citations · 0 references

Concepts

Abstract

We find all triples of Fibonacci numbers (x; y; z) = (Fi; Fj ; Fn) satisfying the Markov equation x2 + y2 + z2 = 3xyz.