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Splitting Quadratic Forms Over Integers of Global Fields
26
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1969
Year
Geometry Of NumberHasse DomainComputational Number TheoryRing TheoryCommutative AlgebraModular FormFinite FieldGlobal FieldsHasse DomainsReal Algebraic Geometry
We are interested in decomposition of quadratic forms over Hasse domains of global fields. By a global fleld F we mean either an algebraic number field or an algebraic function field in one variable over a finite constant field. Throughout assume that characteristic of F is not 2. A Hasse domain o of F is a Dedekind domain which can be obtained as intersection of almost all valuation rings on F. So o is ring of integers corresponding to a set S of almost all discrete spots on F. This is accepted generalization of situation in which F is field Q of rational numbers and o is ring Z of rational integers, or where F is an algebraic number field and o is usual ring of integers contained therein. See O'Meara 2 [6], p. 79, and [5], Chapter X, or Weiss [9], pp. 189 ff. Now consider a regular quadratic space V over global field F. With o a Hasse domain in F, we consider an o-lattice L on V; that is, L is a finitely generated o-module which spans V. We ask following question: Is there some number no, depending only on o, such that L has a non-trivial orthogonal splitting L L,1 IL2 whenever rank L nO? This problem has been investigated in case in which F== Q with Hasse domain o =Z. In fact, Erd6s and Ko [2] proved that in this situation for every integer n > 5 there exists an indecomposable definite quadratic form of rank n. This means that there does not exist a number no in definite case! But indefinite case was later investigated by G. L. Watson in his book Integral Quadratic Forms [8], where he proved that every indefinite Z-form of rank n ? 12 splits non-trivially, and in fact that with a slight restriction on behavior at archimedean spot, splitting occurs when n ? 8. Watson goes on to remark that the general problem of deconlposition has not received attention it deserves. It is our purpose in this
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