arXiv (Cornell University) · 2014 · 58 citations · 4 references
Natural SciencesVisualizationColor TheoryCombinatoricsComputational GeometryGraph ColoringGraph TheoryColoring TheoremsEdge ColoringVertex Coloring
Let $G=(V_1(G),V_2(G),E(G))$ be a bipartite multigraph, and $R\subseteq V_1(G)\cup V_2(G)$. A proper coloring of edges of $G$ with the colors $1,\ldots,t$ is called interval (respectively, continuous) on $R$, if each color is used for at least one edge and the edges incident with each vertex $x\in R$ are colored by $d(x)$ consecutive colors (respectively, by the colors $1,\ldots,d(x))$, where $d(x)$ is a degree of the vertex $x$. We denote by $w_1(G)$ and $W_1(G)$, respectively, the least and the greatest values of $t$, for which there exists an interval on $V_1(G)$ coloring of the multigraph $G$ with the colors $1,\ldots,t$. In the paper the following basic results are obtained. \textbf{Theorem 2.} For an arbitrary $k$, $w_1(G)\leq k\leq W_1(G)$, there is an interval on $V_1(G)$ coloring of the multigraph $G$ with the colors $1,\ldots,k$. \textbf{Theorem 3.} The problem of recognition of the existence of a continuous on $V_1(G)$ coloring of the multigraph $G$ is $NP$-complete. \textbf{Theorem 4.} If for any edge $(x,y)\in E(G)$, where $x\in V_1(G)$, the inequality $d(x)\geq d(y)$ holds then there is a continuous on $V_1(G)$ coloring of the multigraph $G$. \textbf{Theorem 1.} If $G$ has no multiple edges and triangles, and there is an interval on $V(G)$ coloring of the graph $G$ with the colors $1,\ldots,k$, then $k\leq|V(G)|-1$.
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